Ruhiges IT-Forum

Code: Alle auswählen

SELECT count(hosts.computer_name) AS count_double,hosts.computer_name
from hosts
group by hosts.computer_name
having count(hosts.computer_name) > 1

Code: Alle auswählen

SELECT h.uuid, h.computer_name
FROM hosts h
JOIN (
    SELECT computer_name
    FROM hosts
    GROUP BY computer_name
    HAVING COUNT(computer_name) > 1
) dup ON h.computer_name = dup.computer_name
ORDER BY h.uuid;

Code: Alle auswählen

WITH x AS (
  SELECT
    uuid,
    computer_name,
    last_seen_on,
    COUNT(*) OVER (PARTITION BY computer_name) AS cnt,
    MAX(last_seen_on) OVER (PARTITION BY computer_name) AS last_seen_max
  FROM hosts
)
SELECT uuid, computer_name, last_seen_on
FROM x
WHERE cnt > 1
  AND last_seen_on < last_seen_max 
ORDER BY computer_name, last_seen_on;