Hello,
I'm trying to get a list of the software installed on our network (just the name, no need for the version) along with the number of installations for each.
The query "List Normalized Softwares" described in viewtopic.php?t=1840 doesn't seem to work on WAPT 2.6.0.17392; I only get a blank page.
Could you please help me get it working again?
Thank you in advance for your help.
Best regards.
[RESOLVED] Query updated
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Community Forum Rules
* English support on www.reddit.com/r/wapt
* French community support is available on this forum
* Please prefix the topic title with [RESOLVED] if it is resolved.
* Please do not edit a topic that is tagged [RESOLVED]. Open a new topic referencing the old one.
* Specify the installed WAPT version, full version, and build number (2.2.1.11957 / 2.2.2.12337 / etc.) as well as the Enterprise/Discovery edition.
* Versions 1.8.2 and earlier are no longer supported. The only questions accepted regarding version 1.8.2 are related to upgrading to a supported version (2.1, 2.2, etc.).
* Specify the server OS (Linux/Windows) and version (Debian Buster/Bullseye - CentOS 7 - Windows Server 2012/2016/2019).
* Specify the OS of the administration/package creation machine and the machine with the problematic agent, if applicable (Windows 7/10/11/Debian 11/etc.).
* Avoid asking multiple questions when opening a topic, otherwise it may be ignored. If there are multiple topics, open separate topics, preferably one after the other and not all at the same time (i.e., do not spam the forum).
* Include code snippets, screenshots, and other images directly in the post. Links to Pastebin, Bitly, and other third-party sites will be systematically removed.
* As with any community forum, support is provided voluntarily by members. If you require commercial support, you can contact Tranquil IT's sales department at 02.40.97.57.55
Good morning,
If you do not have a standardized name for your fleet, you can use the "original_name" field
If you do not have a standardized name for your fleet, you can use the "original_name" field
Code: Select all
select
n.original_name,string_agg(distinct lower(h.computer_name), ','),count(distinct h.uuid)
from hostsoftwares s
left join normalization n on (n.original_name = s.name) and (n.key = s.key)
left join hosts h on h.uuid = s.host_id
where (n.original_name is not null) and (n.original_name<>'') and not n.windows_update and not n.banned
group by 1